要实现一个函数，该函数使用 printf 打印枚举值，并返回对应的字符串表示，我们可以根据给定的 enum 定义来创建一个字符串映射。下面是一个简单的示例代码：
#include <stdio.h>
typedef enum _Nome_Rule_Action {
NOME_ACTION_NONE = 0,
NOME_ACTION_KEEP_ERR_LEVEL = 1 << 0,
NOME_ACTION_CHANGE_ERR_LEVEL = 1 << 1,
NOME_ACTION_CHANGE_ERR_ATTR = 1 << 2,
NOME_ACTION_ADD_ERR_ATTR = 1 << 3,
NOME_ACTION_DEL_ERR_ATTR = 1 << 4,
NOME_ACTION_IGNORE_EVENT = 1 << 5,
NOME_ACTION_IGNORE_EVENT_IN_MANUAL = 1 << 6,
NOME_ACTION_REPORT_EVENT = 1 << 7,
NOME_ACTION_DELAY_SEND_TO_CLOUD_BY_VEH_STATUS = 1 << 8,
NOME_ACTION_IGNORE_ERRCODE = 1 << 9,
NOME_ACTION_IGNORE_ERRCODE_WITH_ERR_LEVEL = 1 << 10,
NOME_ACTION_REMOVE_ERRCODE_WITH_ERR_LEVEL = 1 << 11,
NOME_ACTION_SWITCH_VEH_OPERATION_STATE = 1 << 12,
NOME_ACTION_SET_RECOVER_TRIP_TIME = 1 << 13,
NOME_ACTION_SET_UOS_REBOOT_TIME = 1 <<14,
NOME_ACTION_CHANGE_ERR_ATTR_WITH_THRESHOLD = 1 <<15,
NOME_ACTION_ADD_ERR_ATTR_WITH_THRESHOLD = (1<<16),
NOME_ACTION_DOWNGRADE_ERR_LEVEL_3 =(1<<17),
NOME_ACTION_DOWNGRADE_ERR_LEVEL_4 =(1<<18),
NOME_ACTION_DOWNGRADE_ERR_LEVEL_5 =(1<<19),
} nome_rule_action_t;
const char* nome_action_to_string(nome_rule_action_t action) {
switch (action) {
case NOME_ACTION_NONE:
return "NOME_ACTION_NONE";
case NOME_ACTION_KEEP_ERR_LEVEL:
return "NOME_ACTION_KEEP_ERR_LEVEL";
case NOME_ACTION_CHANGE_ERR_LEVEL:
return "NOME_ACTION_CHANGE_ERR_LEVEL";
case NOME_ACTION_CHANGE_ERR_ATTR:
return "NOME_ACTION_CHANGE_ERR_ATTR";
case NMEO_ALLOW_ADDITIONAL_ERRORS:
return "NME_ALLOW_ADDITIONAL_ERRORS";
// Add more cases for other actions...
default:
return "UNKNOWN ACTION";
}
}
int main() {
nome_rule_action_t action = C_ERROR;
printf("Action value: %d, Action string: %s\n", action, nome_action_to_string(action));
return0;
}
在这个代码中，我们定义了一个名为 nome_action_to_string 的函数，它接收一个 nome_rule_action_t 类型的枚举值，返回对应的字符串表示。在主函数中，我们打印出该动作的整数值和它对应的字符串。
请注意，你需要添加更多的 case 来覆盖所有枚举值。如果某个枚举值不在列表中，它将返回 "UNKNOWN ACTION"。
内容由零声教学AI助手提供，问题来源于学员提问
